5x^2+6x+144005x=0

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Solution for 5x^2+6x+144005x=0 equation:



5x^2+6x+144005x=0
We add all the numbers together, and all the variables
5x^2+144011x=0
a = 5; b = 144011; c = 0;
Δ = b2-4ac
Δ = 1440112-4·5·0
Δ = 20739168121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20739168121}=144011$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(144011)-144011}{2*5}=\frac{-288022}{10} =-28802+1/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(144011)+144011}{2*5}=\frac{0}{10} =0 $

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